The Electrolysis Calculator is a scientific tool used to calculate the amount of substance deposited or liberated during electrolysis, the electric current required, or the time needed for a given reaction. It is based on Faraday's laws of electrolysis, which relate the quantity of material to electric charge.
This calculator allows users to instantly determine how much metal, gas, or compound will form at electrodes without manually working through electrochemical equations. It is widely used in chemistry labs, industrial electroplating, battery technology, and materials science.
In simple terms, it converts complex electrical and chemical relationships into accurate, quick results.
Electrolysis is a chemical process in which electrical energy drives a non-spontaneous redox reaction. When current passes through an electrolyte, ions move toward electrodes:
Cations migrate to the cathode to gain electrons (reduction)
Anions migrate to the anode to lose electrons (oxidation)
The amount of substance deposited or liberated is directly proportional to the electric charge passed through the electrolyte, as described by Faraday's laws.
Electrolysis is a fundamental principle in metal extraction, electroplating, and electrochemical synthesis.
Faraday's First Law of Electrolysis:
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m = (Q × M) / (n × F)
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Faraday's Second Law of Electrolysis:
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Q = I × t
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Where:
m = Mass of substance deposited or liberated
Q = Total electric charge (Coulombs)
M = Molar mass of the substance
n = Number of electrons transferred per ion
F = Faraday's constant (96485 C/mol)
I = Electric current (Amperes)
t = Time (seconds)
Simplified Mass Formula:
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m = (I × t × M) / (n × F)
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These formulas are highlighted in a frame in the calculator interface for better user experience and clarity.
Example: Deposit copper using a 2 A current for 30 minutes.
Molar mass of Cu, M = 63.55 g/mol
n = 2 (Cu²⁺ → Cu)
I = 2 A
t = 30 min = 1800 s
Step 1: Calculate total charge
Q = I × t = 2 × 1800 = 3600 C
Step 2: Apply Faraday's first law
m = (Q × M) / (n × F)
m = (3600 × 63.55) / (2 × 96485)
m ≈ 1.18 g
Result: Approximately 1.18 grams of copper will be deposited.