The Eigenvalue Calculator is a tool that helps calculate the eigenvalues of a square matrix. Eigenvalues are scalar values that describe the scaling factor of a matrix transformation. When a matrix is multiplied by a vector (called an eigenvector), the resulting vector is a scaled version of the original, and the scaling factor is the eigenvalue.
This calculator works by finding the roots of the characteristic equation of the matrix, which is used to determine the eigenvalues.
Eigenvalues:
Scalar values that, when a matrix is multiplied by an eigenvector, result in a scaled version of the eigenvector.
Eigenvectors:
Non-zero vectors that remain in the same direction after a matrix transformation, only scaled by the corresponding eigenvalue.
Characteristic Equation:
The equation obtained by subtracting λ times the identity matrix from the original matrix, and then calculating its determinant. The roots of this equation are the eigenvalues of the matrix.
Matrix:
A rectangular array of numbers arranged in rows and columns, often used to represent linear transformations.
Linear Algebra:
The branch of mathematics that studies vector spaces and linear transformations, which is where eigenvalues and eigenvectors are extensively used.
To calculate the eigenvalues of a matrix, we use the characteristic equation:
The Characteristic Equation:
Given a matrix A, the eigenvalues λ are the roots of the following equation:
det(A − λI) = 0
Where:
A is the square matrix.
λ is the eigenvalue.
I is the identity matrix of the same dimension as A.
For a 2x2 matrix:
A = [a b]
[c d]
The characteristic equation becomes:
det(A − λI) = |a − λ b|
|c d − λ| = 0
Solving the determinant:
(a − λ)(d − λ) − bc = 0
Expanding and simplifying:
λ² − (a + d)λ + (ad − bc) = 0
The solutions to this quadratic equation are the eigenvalues.
For larger matrices, the characteristic equation becomes more complex and typically requires solving higher-degree polynomials.
Pro Tip: Present this formula in a highlighted frame to improve readability and user experience.
Problem: Find the eigenvalues of the matrix:
A = [4 1]
[2 3]
Step 1:
Write the characteristic equation:
det(A − λI) = 0
|4 − λ 1|
|2 3 − λ| = 0
Step 2:
Compute the determinant:
(4 − λ)(3 − λ) − (2)(1) = 0
(4 − λ)(3 − λ) − 2 = 0
Step 3:
Expand the equation:
12 − 4λ − 3λ + λ² − 2 = 0
λ² − 7λ + 10 = 0
Step 4:
Solve the quadratic equation:
λ = [−(−7) ± √((−7)² − 4(1)(10))] / 2(1)
λ = [7 ± √(49 − 40)] / 2
λ = [7 ± √9] / 2
λ = [7 ± 3] / 2
The eigenvalues are:
λ₁ = (7 + 3) / 2 = 5, λ₂ = (7 − 3) / 2 = 2
Result: The eigenvalues of matrix A are 5 and 2.