A Neutralization Calculator is a scientific tool used to determine the exact amount of acid or base required to neutralize another solution. It helps calculate how much of one substance is needed to reach a neutral pH (around 7) or a target pH level after a chemical reaction.
This calculator simplifies complex acid–base reaction math, making it fast and accurate for laboratory, educational, industrial, and environmental applications.
Neutralization is a chemical reaction where an acid reacts with a base to form salt and water. This process is a core part of acid–base chemistry and follows balanced chemical equations.
For example:
Hydrochloric Acid + Sodium Hydroxide → Sodium Chloride + Water
HCl + NaOH → NaCl + H₂O
Understanding molarity, volume, and reaction stoichiometry is essential for accurate neutralization.
Neutralization calculations are based on the mole relationship between acid and base.
Core Neutralization Formula
M₁ × V₁ × n₁ = M₂ × V₂ × n₂
Where:
M = Molarity (mol/L)
V = Volume (L)
n = Number of H⁺ or OH⁻ ions produced per molecule
Highlighted Formula Frame
Required Volume = (M₁ × V₁ × n₁) ÷ (M₂ × n₂)
This formula ensures the number of moles of acid equals the number of moles of base at the equivalence point.
Problem: How much 0.5 M NaOH is needed to neutralize 100 mL of 1 M HCl?
Step 1: Write Known Values
M₁ (HCl) = 1 M
V₁ (HCl) = 0.1 L
n₁ = 1 (HCl releases 1 H⁺)
M₂ (NaOH) = 0.5 M
n₂ = 1 (NaOH releases 1 OH⁻)
Step 2: Apply Formula
V₂ = (M₁ × V₁ × n₁) ÷ (M₂ × n₂)
V₂ = (1 × 0.1 × 1) ÷ (0.5 × 1)
V₂ = 0.2 L
Final Answer
You need 0.2 liters (200 mL) of NaOH to neutralize the acid.